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1.3x^2-15x-15=0
a = 1.3; b = -15; c = -15;
Δ = b2-4ac
Δ = -152-4·1.3·(-15)
Δ = 303
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{303}}{2*1.3}=\frac{15-\sqrt{303}}{2.6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{303}}{2*1.3}=\frac{15+\sqrt{303}}{2.6} $
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